Question

calculate the molarity of 1.8 g of HNO3 dissolved in 250 ml aqueous solution​

Answer 1

Given:

Mass of HNO₃ = 1.8g

Volume = 250ml

To find:

The molarity of 1.8g of HNO₃ dissolved in 250ml aqueous solution​.

Solution:

Molarity = Mole / Volume(L)

Molarity = (Mass × 1000) / (M.wt. × vol(ml))

M.wt of HNO₃ = 1 + 14 + (3 × 16)

M.wt of HNO₃ = 15 + 48

M.wt of HNO₃ = 63

Molarity = (Mass × 1000) / (M.wt. × vol(ml))

Molarity = (1.8 × 1000) / (63 × 250)

Molarity = 1800 / 15750

Molarity = 0.1143M

Therefore, molarity of 1.8g 0f HNO₃ dissolved in 250ml of aqueous solution is 0.1143M.

Answer 2

Answer:

Step-by-step explanation:

1.8 gm HNO3 in 250 ml