Question

calculate the molarity of 10gm of glucose in 90 gm of water​

Answer 1

In order to know your answer firstly know about molality

Molality may be defined as the number of moles of solute that are dissloved in a kg of water .

so firstly we have to calculate the moles of glucose

10*1/180.16 = 0.0555 ( as the molar mass of glucose= 180.1559)

These are dissloved in 90 g of water.

first convert mass into kilogram =90/1000= 0.090 kg

0.090 kg water = 0.0555 moles of glucose

so 1 kg of water=1*0.0555/0.090 = 0.6166 moles of glucose

round about of 0.6166 will be 0.617 which is our answer

Answer 2

Answer:

Explanation:

IN THE QIUESTION U ARE TOLD TO FIND MOLARITY.

WEIGHT OF THE GLUCOSE GIVEN=10 GRAM

MOLAR MASS OFGLUCOSE =180 GRAM

MOLES=W/M.M=1/18

USINNG THE FORMULA-

V/22.4=1/18

YOU WILL GET 1.24 ML AS YOUR VOLUME OF GLUCOSE.

WEIGHT OF THE WATER IS GIVEN AS 90 GRAM

MOLAR MASS OF WATER=18 GRAM

MOLES=W/M.M=90/18=5

USING THE FORMULA-

v/22.4=5

you will get THE VOLUME OF WATER AS 112.0 ML

NOW, THE VOLUME OF SOLUTION= VOLUME OF WATER+VOL. OF GLUCOSE

=112.0+1.24

=113.24ML

WE KNOW THAT,

MOLARITY =MOLES OF SOLUTE/VOLUME OF SOLUTION

=1/18/(113.24ML/1000)=0.49 AS YOUR FINAL ANSWER.

I HOPE MY ANSWER HAS HELPED YOU