Math, asked by bhavani37, 1 year ago

if 0.35 28 is expressed in the form of p by 2 power n into 5 power n find the smallest value of n m and p​

Answers

Answered by vyshnavireddy
13

Answer:

Step-by-step explanation:

now p/2^n x 5^m

3528/1000 = its simplest form will be 441/1250

now smallest values of

p=441

n=1

m=4

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Answered by pinquancaro
12

The smallest value of n=1, m=4 and p-441.

Step-by-step explanation:

Given : Number 0.3528 is expressed in the form of p by 2 power n into 5 power n.

To find : The smallest value of n, m and p​ ?

Solution :

Number 0.3528, remove decimal and convert into required form.

0.3528=\frac{3528}{10000}

0.3528=\frac{3528}{10^4}

0.3528=\frac{3528}{(2\times 5)^4}

0.3528=\frac{3528}{2^4\times 5^4}

Converting into smallest value,

0.3528=\frac{441}{2^1\times 5^4}

On comparing, p=441, n=1 and m=4

Therefore, the smallest value of n=1, m=4 and p-441.

#Learn more

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