Calculate the molarity of 10ml of NAOH present in 1000ml of solution
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We have to find that the molarity of 10 ml of NaOH present in 1000 ml of solution
for 1000ml it's weight is 40 gms
that implies for 10 ml it's weight is 0.2 gms
Therefore,molarity=weight/gram molecular weight*1000/volume(in ml)
0.2/40*1000/10
=0.5
for 1000ml it's weight is 40 gms
that implies for 10 ml it's weight is 0.2 gms
Therefore,molarity=weight/gram molecular weight*1000/volume(in ml)
0.2/40*1000/10
=0.5
nehakulkarni331:
thanx
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