Calculate the molarity of 20% solution of KOH by mass whose density is 1.02g/ml.
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We know that
M = [(m/M)% × d × 10]/GMM
where(m/M)% = mass by mass % = 20% (given)
d = density =1.02g/ml
GMM = gram molar mass of KOH = 56g
M = Molarity
Put the values in formula
M = (20 × 1.02 ×10)/56
M = 4M You know that unit of Molarity is M.
Hope I am correct
Please mark this answer as a brainlist answer if I am correct and if you like the answer
Please tell me whether you know the above formula or not
M = [(m/M)% × d × 10]/GMM
where(m/M)% = mass by mass % = 20% (given)
d = density =1.02g/ml
GMM = gram molar mass of KOH = 56g
M = Molarity
Put the values in formula
M = (20 × 1.02 ×10)/56
M = 4M You know that unit of Molarity is M.
Hope I am correct
Please mark this answer as a brainlist answer if I am correct and if you like the answer
Please tell me whether you know the above formula or not
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