Question

calculate the molarity of 3.65 % weight by volume aqua solution of HCL​

Answer 1

Answer:

this is the answer for the question

Answer 2

Answer:

#"Molarity"-="Moles of solute"/"Volume of solution"#

Explanation:

And here, "molarity"=((3.65*g)/(36.5*g*mol^-1))/(500*mLxx10^-3*L*mL^-1)=0.200*mol*L^-1.

Is the calculation consistent dimensionally?

And thus if it is 0.200*mol*L^-1 with respect to hydrogen chloride, it is 0.200*mol*L^-1 with respect to H_3O^+, AND Cl^-.

hope you understand the answer dear....