Question

calculate the molarity of 49% H₂So4 solution by mass. if the density of the solution is 1.5 g/ml.​

Answer 1

Answer:

33.4 mL volume of the stock solution for it's Solution:- Stock solution is 49% w/w. 49% ww solution as: It means 49 grams of sulfuric acid 100g(1mL1.5g) present in 100 grams of the solution. =66.7mL We want to make 2.5 L of 0.1M sulfuric acid solution from the stock are present in 66.7mL solution. We solution. let's calculate the moles need to calculate the volume of this and then grams of this diluted solution from it's given volume and 24.5 grams of sulfuric acid. molarity as: 2.5L(0.1mol1L)(98g1mol)

24.5gH2SO4(66.7mL49g)

=24.5g

=33.4mLH2SO4

So, 33.4 mL of stock solution are Density of the stock solution is 1.5 required to make 2.5L of 0.1M gram per mL. Let's calculate the sulfuric acid solution.

Answer 2

Answer:

7.5

Explanation:

molarity=%mass×density×10/molar mass of solute

molarity=49×1.5×10/98

molarity=15/2=7.5