Calculate the molarity of a solution obtained by mixing 100 mL of
0.3 M H2SO4 and 200 mL of 1.5M H2SO4
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We know that
M1v1+M2v2 = MmixVmix
M1 = 0.3 M
V1= 100 ml
M2= 1.5M
V2= 200ml
Vmix= 300ml
Now we have to find Mmix.
Now
0.3*100 + 1.5*200 = 300 Mmix
30+300= 300*Mmix
330/300 = Mmix
1.1 = Mmix
M1v1+M2v2 = MmixVmix
M1 = 0.3 M
V1= 100 ml
M2= 1.5M
V2= 200ml
Vmix= 300ml
Now we have to find Mmix.
Now
0.3*100 + 1.5*200 = 300 Mmix
30+300= 300*Mmix
330/300 = Mmix
1.1 = Mmix
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