Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.04. [ Assume the density of water to be 1 ]
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Moles of ethanol = 0.04 mol
Moles of water = 1-0.04 = 0.96 mol
Mass of water = 0.96 mol x 18 g/mol = 17.3 g
Mass of ethanol = 0.04 mol x 46 g/mol = 1.84 g
Mass of the solution = 17.3 g + 1.84 g = 19.1 g
Assuming density of solution to be 1 g/ml,
Volume of solution = mass/density = 19.1/1 = 19.1 ml = 0.0191 L
Molarity is the number of moles of solute present in 1L of solution,
Molarity = 0.040/0.0191 = 2.1 M
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