Question

Calculate the molarity of a solution which contains 5.85gm of NaCl per 500ml.

Do it fast.......

Answer 1

No. of moles of NaCl in 500 mL,n

= given mass of NaCl/ Molar mass of NaCl

= 5.85/58.5

= 1/10

so, n = 0.1

Since there is 0.1 moles of NaCl in 500 mL

so, in 1000 mL( 1 L) it will be 1000/500 * 0.1

= 0.2 moles / 1000 mL (1 L)

As Molarity is equal to the moles of solute divided by the liters of solution.

so , M = n/ L = 0.2/ 1 = 0.2 M

Answer 2

Hi friend,

Molarity = 0.2M

✔Solution is here :-

➡Molarity = mole/volume

➡Molecular mass of NaCl =
23 + 35.5 = 58.5

➡Moles = given mass/molecular mass

= 5.85/58.5
= 0.1

➡Then, turn ml into Liter :-

1 L = 1000ml
1/1000 L = 1ml

➡Therefore, 500ml = 1/2 liter = 0.5 L

So, Molarity = 0.1/0.5
= 1/5
= 0.2 ( proved)

_____________________________

Thanks !

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