Calculate the molarity of an aqueous solution containing 3.0g of urea(mol.mass=60) in 100g of water
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I think you mean to ask “Molality” instead of Molarity.
Moles of urea = Weight / GMW
= 3.0 g / (60 g/mol)
= 0.05 mol
Mass of water = 100 g = 0.1 kg
Molality = Moles of solute / Mass of Solvent in kg
= 0.05 mol / 0.1 kg
= 0.5 molal
Molality of given solution is 0.5 m
Moles of urea = Weight / GMW
= 3.0 g / (60 g/mol)
= 0.05 mol
Mass of water = 100 g = 0.1 kg
Molality = Moles of solute / Mass of Solvent in kg
= 0.05 mol / 0.1 kg
= 0.5 molal
Molality of given solution is 0.5 m
Abisha14:
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molality is 5, since density is 1g/cm^3 for water. As moles of urea are 0.5 , substituting the value we get 5M
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