Question

Calculate the molarity of an aqueous solution of glucose containing 1.8 gm of it in 500 ml of solution

Answer 1

Answer:

Your answer is 0.02 M

Explanation:

Molecular formula of glucose =$C_{6}H_{12}O_{6}$

Gram molecular weight of glucose ={(6×12)+(12×1)+(6×16)}g=180 g

According to question, weight of glucose solution =1.8 g

Number of moles of the solution = $\frac{given weight}{gram molecular weight}</p><p>=]\frac{1.8}{180}</p><p>=0.01 moles$

Volume of glucose solution=500 ml=0.5 L

Molarity=$\frac{number of moles}{volume in L}</p><p> =(\frac{0.01}{0.5}) M=0.02 M$___(ans)