Question

Rohit sold his car at 10% below the cost price to Amit Amit got the car repaired and spent rupees 5000 he then sold the car to Rajesh at 20% above the total cost which is equal to 100000 find the original price of the car nearest to the hundred​

Answer 1

Answer:

87,000

Step-by-step explanation:

C.P. of car for Amit =

90 × y

= Rs.

9y

100 10

Actual C.P. = Rs.   9y + 5000  

10

According to the question,

 9y + 5000  × 120 = 100000

10 100

⇒

9y

+ 5000 =

100000 × 100

≈ 83300

10 120

⇒

9y

≈ 83300 - 5000 ≈ 78300

10

⇒ y ≈

78300 × 10

≈ Rs. 87000

9