Question

Calculate the molarity of an aqueous solution of Na2CO2if 15ml of the Na2CO3 solution is required to neutralise 20ml 0.01M HCL solution.

Answer 1

Explanation:

Neutralisation reaction -

Na2CO3 + HCl---> NaCl + H2O

this is a balanced equation.

Same no. Of moles of Na2CO3 is required as of mole of HCl.

Molarity of HCl = 0.01 = no. Of mol x 1000/vol.

0.01 = no. Of moles x 1000/20

No. Of moles = 0.01x20/1000 = 0.0002

Molarity of NaOH = 0.0002 x 1000/15

= 0.013M

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