Calculate the molarity of NaOH in the solution prepared by dissolving its 4 g in enough water to form 250 mL of the solution
NCERT Class XII
Chemistry - Main Course Book I
Chapter 1. Some Basic Conpepts of Chemistry
Answers
Answered by
837
Molarity(M) = w × 1000 / GMW × V
where,
w = given weight of the solute = 4g
GMW = Gram Molecular Weight of the solute = 40g
V = Volume of the solution in ml. = 250 ml
So,
M of NaOH
= 4 × 1000 / 40 × 250
= 0.4 M
where,
w = given weight of the solute = 4g
GMW = Gram Molecular Weight of the solute = 40g
V = Volume of the solution in ml. = 250 ml
So,
M of NaOH
= 4 × 1000 / 40 × 250
= 0.4 M
Answered by
356
Molarity (M) = No. of moles of solute/Volume of solution in litres No. of moles= mass of NaOH / molar mass of NaOH = 4g / 40g = 0.1 molecular Volume = 250 / 1000Lit = 0.250L M= 0.1 mol/ 0.250L = 0.4M
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