Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the frequency of emission, (b) distance traveled by this radiation in 30 s (c) energy of quantum and (d) number of quanta present if it produces 2 J of energy.
NCERT Class XII
Chemistry - Main Course Book I
Chapter 2. Structure of Atom
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λ = wavelength = 616 nm
frequency of an electro magnetic radiation = f = c / λ
f = 2.98 * 10⁸ / 616 * 10⁻⁹ = 4.837 * 10¹⁴ Hz
distance = 2.98 * 10⁸ m/sec * 30 sec = 8.94 * 10⁹ meters
= 8,940,000 km
energy in one photon or quantum : E = h f = 6.626 * 10⁻³⁴ * 4.837 * 10¹⁴
= 3.205 * 10⁻¹⁹ J = 2 eV
number of quanta = energy / energy per quantum
= 2 J / 3.205 * 10⁻¹⁹
= 6.239 * 10¹⁸ number of photons or quanta
frequency of an electro magnetic radiation = f = c / λ
f = 2.98 * 10⁸ / 616 * 10⁻⁹ = 4.837 * 10¹⁴ Hz
distance = 2.98 * 10⁸ m/sec * 30 sec = 8.94 * 10⁹ meters
= 8,940,000 km
energy in one photon or quantum : E = h f = 6.626 * 10⁻³⁴ * 4.837 * 10¹⁴
= 3.205 * 10⁻¹⁹ J = 2 eV
number of quanta = energy / energy per quantum
= 2 J / 3.205 * 10⁻¹⁹
= 6.239 * 10¹⁸ number of photons or quanta
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