Calculate the molarity of solution contain 4g of NaOH in 1000ml of solution.
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Given:-
→Mass of NaOH = 4g
→Volume of solution = 1000mL
To find:-
→Molarity of the solution
Solution:-
•Atomic mass of Sodium(Na) = 23u
•Atomic mass of Oxygen(O) = 16u
•Atomic mass of Hydrohen(H) = 1u
Thus, molecular mass of NaOH :-
= 23+16+1
= 40u
We know that, molar mass is the molecular mass in grams. Thus, molar mass of NaOH is 40g.
No, of moles in 4g of NaOH:-
= Given Mass/Molar mass
= 4/40
= 0.1 mole
Now we know that:-
Molarity of a soution:-
= Moles of solute/Liters of solution
=>1000mL = 1L
= 0.1/1
= 0.1 M
Thus, molarity of the solution is 0.1 M .
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