Question

calculate the molarity of the following
30 g of co(No3).6H2Oin 4.3 l of soln​

Answer 1

Explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

$Molecular \: weight \: of \: Co(No_3).6H_2O \: is \\ \\ 58.93 + 14 + (16 \times 3) + 18 \times 6 \\ \\ 228.93$

$mole (n) = \frac{Given \: weight}{Molecular \: weight} \\ \\ mole (n) = 0.131 moles$

$Molarity = \frac{no. \: of \: moles \: of \: solute}{Volume \: of \: solution} \\ \\ Molarity = \frac{0.131}{4.3} \\ \\ \huge\boxed{ Molarity = 0.0305 M}$

Answer 2

Answer:

The answer is 0.034 M

I hope it will help you