Question

Calculate the molarity of the solution obtained on mixing 100 ml of 0.2 M H2SO4 with 50 ml of 0.1 M HCl.

Answer 1

Explanation:

i hope is useful..........

Answer 2

Answer:

The molarity of solution obtained on mixing both the solutions is 0.166M

Explanation:

The given data is

(i)Sulphuric Acid

Volume of the solution is

$V _{1} = 100ml$

Molarity of the solution is

$M_{1} = 0.2M$

(ii)Hydrochloric Acid

Volume of the solution is

$V_{2}=50ml</p><p>$

Molarity of the solution is

$M_{2}=0.1M$

Let the molarity of the mixed solution be M

The total volume of solution obtained is

$V=V_{1}+V_{2} = 100 + 50 \\ = 150ml$

Since,the number of moles are constant for individual and mixed fluids,we have the relation to find molarity as given below

$MV=M_{1}V_{1}+M_{2}V_{2}$

Substituting the given values we get

$M \times 150 = 0.2 \times 100 + 0.1 \times 50 \\ = > M \times 150 = 25 \\ = > M = \frac{25}{150} = \frac{1}{6} = 0.166M$

Therefore,The molarity of solution obtained on mixing both the solutions is found to be 0.166M

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