Find zeros of p(x)= root 3x-3
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Solution:
Given p(x) = √3x-3
To find zeroes of p(x), we must
take p(x) = 0,
=> √3x-3 = 0
=> √3(x-√3)=0
=> x-√3=0
=> x = √3
Therefore,
√3 is zero of p(x)
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Hey !
Refer the below attachment !
Thanks !
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