Question

If the side of a square is tripled how many times will its area be compared to the area of the original square

Answer 1

Square is a quadrilateral with four sides .

Area of square =$s^{2}$

where s is the side of the square.

Let the side of square be s.

Its area will be= $s^{2}$-------(1)

According to the question,

Side of square is tripled ,so the side becomes = 3s

Its area will be

$A_2= 3s^{2}$

$A_2=9s^{2}$---------(2)

On dividing eq(1) by (2)

$\dfrac{A}{A_2} = \dfrac{s^{2} }{9s^{2} }$

On solving we get

$\dfrac{A}{A_2} = \dfrac{1}{9}$

$\large \boxed{9A = A_2}$

So, the new area will be thrice the original one

Answer 2

Let the side of square be s.

$\mathbb\pink{Its \:area\: will \:be}$

$A = {s}^{2}$ ---------eq(1)

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$\mathfrak\purple{According \:to\: the\: question,}$

When the side of square is tripled,

The side becomes = 3s

$\mathbb\pink{Its \:area\: will \:be}$

$A' = {(3s)}^{2}$

$A' =9s^{2}$ ---------eq(2)

$\mathfrak\purple{On \:dividing \:eq(1) \:by \:eq(2)}$

$\dfrac{A}{A'} = \dfrac{s^{2} }{9s^{2} }$

$\dfrac{A}{A'} = \dfrac{1}{9}$

$\large \boxed{9A = A'}$

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$\mathfrak\purple{Answer\: :-}$

The new area will be nine times the original one