Question

calculate the mole fraction molarity and molality of HNO3 in a solution containing 12.2% HNO3 given that density of HNO3 equals to 1.038gram/cm3

Answer 1

this example help u


let us first calculate molality

let mass of water be 100x

therefore mass of nitric acid = 69x

molality= 69 x 10/ 1000=690/1000 = 6.9

in sums like this where 1he density of water is not given we assume it to be 1g/ ml

now mass of nitric acid in 1000 ml of solution = 690       ( 1g = i ml )

therefore molarity= 690/1000 x 1.41



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