Question

Calculate the mole fraction, molarity and molality of NH3 if it is in
solution composed of 30.6 g NH3 in 81.3 g of H2O. The density of the
solution is 0.982 g/mL and the density of water is 1.00 g/mL​

Answer 1

Answer:

Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that, through cellular respiration, can later be released to fuel the organism's activities

Answer 2

First of all let's calculate the molar weight of

NH3 =14+ 3= 17g

H2O =2 + 16= 18g

Now let's calculate the number of moles of

NH3 in 30.6g by dividing it by molar weight = 30.6/17 = 1.8 moles

Similarly, the number of moles of H20 in 81.3g = 81.3/18 = 4.5

Mole fraction = number of moles of solute/number of moles of solvent = 1.8/4.5 = 0.4

Molality = number of moles of solute /weight of solvent in kg = 1.8/81.3 X 1000 = 22 moles per gm of water

Molarity = number of moles of solute / volume of solvent in L = 1.8/81.3 × 1000 = 22 M per mL of water

Now except for the units, the molarity and molality is the same in this case, this is because, density of water is 1g per mL at room temperature.