Question

Calculate the mole fraction of benzene (C6H6) in solution containing 30% by mass in CCl4 ?

Answer 1

SoluTion :-

Mass % is given so take total mass of the solution = 100 g

Then the mass of benzene      =  30 % of 100 = 30 g.

Mass of carbon tetrachloride   =  Total mass  - Mass of benzene

= (100 − 30) g

= 70 g

Molar mass of benzene (C6H6) = 6 × 12 + 6 × 1 = 78 g mol−1

Formula

$\sf {Number\ Of\ Moles = \frac{Mass}{Molar\ Mass} }$

$\sf {Number\ of\ moles\ of\ C_{6}H_{6} =\frac{30}{78}=0.3846\ mol }$

Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 355 = 154 g mol−1

$\sf {Mole\ fraction\ of\ a\ component = \frac{Mo.\ of\ moles\ of\ component}{Total\ no.\ of\ moles} }$

$\sf {Mole\ fraction\ of\ benzene =\frac{0.3846}{0.3846+0.4545}=0.458 }$

$\sf {Number\ of\ moles\ of\ CCl_{4} = \frac{70}{154} = 0.4545\ mol}$

Answer 2

Answer:

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Explanation: