Calculate the mole fraction of benzene in a solution which is 30 by mass in ccl4
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Hey !!
Let the mass of solution be 100 g
Mass of Benzene = 30 g
Mass of carbon tetrachloride = 100 g - 30 g = 770 g
Number of moles of benzene = Mass / Molar mass
= 30 g / 78 g mol⁻¹
= 0.385 mol
Number of moles of carbon tetrachloride = Mass / Molar mass
= 70 g / 154 g mol⁻¹
= 0.455 mol
Mole fraction of benzene = Mass of benzene / Moles of benzene + Moles of tetrachloride
= 0.385 mol / 0.840 mol
FINAL RESULT :- 0.458
Hope it helps you !!
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