Question

calculate the mole fraction of each component contained in solution of 20 gram Naoh + 50 gram caco3 + 90 gram of glucose​

Answer 1

Answer:

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Answer 2

Answer:

Mole fraction of 20g of NaOH=0.33333333

Mole fraction of 50g of CaCO3=0.3333333

Mole fraction of 90g of glucose(C6H12O6)=0.3333333

Explanation:

Mole fraction=number moles of solute / number moles of solution