calculate the mole fraction of naoh in asolution containing 20g of naoh per 360g of water
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Answer:
0.121
Explanation:
15% NaOH by mass is 15g of NaOH in (100-15)g of solution.
No. Of moles of NaOH in solution = 0.65
No of moles of Water in solution = 4.72
Mole Fraction = ((Moles of Solvent)(Moles Of Solute)+(Moles of Solvent))
OR
((Moles of Solvent)Total Number Of Moles)
= 0.65 / 5.37
= 0.121
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