Question

Calculate the mole fraction of solute in 10% weight/volume of NaOH (aq) solution. Given density of the solution is 1.5g/ml.​

Answer 1

Explanation:

Formula used:

1.Molarity=number of molesvolume of solution in L.

2.Molality=number of molesmass of solvent in Kg.

3.Mole fraction of component A=number of moles of Atotal number of moles.

4.Molarity =10×1.070×100040×100=2.14 M.

5.Molality =10×100040×90=2.2 m.

6.Mole fraction=0.250.25+9010.

⇒Mole fraction=0.255.25=0.9.