calculate the mole fraction of the solute in an aqueous solution containing 18.0 gram of glucose in 100 gram of water
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Answer:
0.017
Explanation:
Mole fraction is moles of solute upon total no. of moles in a solvent
Mole of solute =18/180=0.1
Mole of solvent=100/18=5.55
Mole fractions=0.1/0.1+5.65=0.017
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