Question

calculate the mole fraction of water in a mixture of 12g water, 108g acetic acid and 92 g of ethanol

Answer 1

moles of water in mixture=12/18=2/3
moles of acetic acid in mixture = 108/60 = 18/10
moles of ethanol in mixture= 92/46 = 2
mole fraction of water = (2/3)/(2/3+1.8+2) = (2/3)/[(2+5.4+6)/3] =2/13.4=20/134 = 10/67
therefore 10/67 is the mole fraction of water in mixture.

hope this helps:p

Answer 2

Answer:

Explanation:    moles of water in mixture=12/18=2/3

moles of acetic acid in mixture = 108/60 = 18/10

moles of ethanol in mixture= 92/46 = 2

mole fraction of water = (2/3)/(2/3+1.8+2) = (2/3)/[(2+5.4+6)/3] =2/13.4=20/134 = 10/67

therefore 10/67 is the mole fraction of water in mixture.

hope this helps:p

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