Question

calculate the mole percentage of ch3oh H and H2O respectively in 60% by mass aqua solution of ch3oh h​

Answer 1

Answer:

Explanation:

60% solution by mass means 60 g of CH3OH and 40 g H2O

mole percentage = mole fraction ×100 = noofmolesofasubstancetotalnoofmoles×100

No. of moles of CH3OH=6032=1.875

No. of moles of H2O=4018=2.22

Total no. of moles = 4.0972

Mole percentage of CH3OH=1.8754.0972×100=45.76

Mole percent of H2O=2.224.0972×54.183

Answer 2

Answer:here is your answer

Explanation:Answer:% CH3OH by mass = 60 %

mass of CH3OH ÷ mass of solution = 60/100

Let, the mass of the solution be 100 gm

Therefore, mass of CH3OH = 60 gm

and mass of H20 = 40 gm

moles of CH3OH = 60/32

moles of H20 = 40/18

% mole of CH3OH =( moles of CH3OH ÷ total moles ) X 100 = [60/32 ÷ (60/32 + 40/18)] X 100

= 45.76%

% mole of H20 = 100 - 45.76 = 54.24%