Question

calculate the molecular masses of ethanoic acid , CH3,COOH​

Answer 1

1.METHANOIC ACID:-

CH3COOH

$\rightarrow$ 12+(1×3)+12(16×2)+1

$\rightarrow$ 62amu.

2.ethanoic acid.

c2h5cooh.

(12×2)+(1×5)+(12)+

(16×2)+1

$\rightarrow$74amu

Answer 2

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Mass of C = 12u

Mass of H = 1u

Mass of O = 16u

Therefore,

Mass of CH3COOH = 12+1×3+12+ 16+16+1

= 12+3+12+16+16+1

=15+12+32+1

= 27+33

= 60g/mol