Question

Calculate the moles of 0.9g of Calcium Carbonate

Answer 1

Answer: 0.009 moles

Explanation: Let us first calculate molecular weight of Calcium Carbonate (CaCO3) = 40×1+12×1+16×3 = 100g

1 mole = 100g

x moles= 0.9g

x= 0.9÷100 moles

x = 0.009 moles.

Therefore the answer is 0.009 moles