Question

Calculate the moles of Hydrogen present in a 500 cm² sample of hydrogen gas at a pressure of 760
of Hg and 27°C.
a) 2.56 x 10-6 mole b) 2.03 x 10-5 mole c) 3.02 x 104 mole d) 2.03 x 10-2 moles
see friendzzz... in this the ans is 2.03×10^5.... so pls help me to find this answer
​

Answer 1

Answer:

The equation is balanced.

3. Solid sodium reacts with water to form aqueous sodium hydroxide

and hydrogen gas.

For balancing:

a. Na(s) + H2O(l) → NaOH(aq) + H2(g)

LHS: 1Na, 2H, 1O RHS: 1Na, 1OH, 2H

b. Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

LHS: 1Na, 4H, 2O RHS: 2Na, 4H, 2O

c. 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

LHS: 2Na, 4H, 2O RHS: 2Na, 4H, 2O

The equation is balanced:

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

4. Ammonia gas breaks down (decomposes) to form nitrogen gas and

hydrogen gas.

For balancing

a. NH3(g) → N2(g) + H2(g)

LHS: 1N, 3H, RHS: 2N, 2H

b. 2NH3(g) → N2(g) + H2(g)

LHS: 2N, 6H RHS: 2N, 2H

c. 2NH3(g) → N2(g) + 3H2(g)

LHS: 2N, 6H RHS: 2N, 6H

The equation is balanced: 2NH3(g) → N2(g) + 3H2(g)

5. Sodium bicarbonate solid decomposes to form sodium carbonate,

carbon dioxide gas and water vapour.

a. NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)

LHS: 1Na, 1H, 1C and 3O RHS: 2Na, 2C, 6O, 2H

b. 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)

Step-by-step explanation:

1. C:O = 3:8 Therefore Mass of O = mass of C x 8/3 = 6 x 8/3 = 16 g

2. H is 1/9 of the total mass: 1/9 x 36 g = 4 g and O is 8/9 of the total

mass: 8/9 x 36 = 32 g.

Activity 2.1.2:

1. Mass product = mass A + mass B = 300g + 100g = 400 g

2. Mass B = Mass AB – Mass A = 25g – 10g = 15 g

3. Mass NaCl = Mass CaCl2 + Mass Na2CO3 - Mass CaCO3 = 2.12g +

2.20g – 2.90g = 1.42 g

4. Mass calcium oxide = Mass calcium + Mass oxygen = 40.0g + 16.0g

= 56.0 g

5. Mass oxygen used up = Mass magnesium oxide - Mass magnesium

= 40.0g – 24.0g = 16.0 g

Activity 2.1.3:

1. Methane gas reacts with oxygen to form carbon dioxide gas and

water vapour.

For balancing:

a. CH4(g) + O2(g) → CO2(g) + H2O(g)

LHS: 1C, 4H, 2O RHS: 1C, 2H, 3O

b. CH4 (g) + O2(g) → CO2(g) + 2H2O(g)

LHS: 1C, 4H, 4O RHS: 1C, 4H, 4O

The equation is balanced: CH4 (g) + O2(g) → CO2(g) + 2H2O(g)

2. Silver nitrate reacts with aqueous sodium chloride to form solid silver

chloride and aqueous sodium nitrate

For balancing:

a. AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

LHS: 1Ag, 1NO3-

, 1Na, 1Cl RHS: 1Ag, 1NO3-

, 1Na, 1Cl

So plz mark my answet in brainliest.

Answer 2

Answer:

the mole of hydrogen is x now find tue value of x mark a s brainliest