Question

Calculate the moment of force of 5 N applied on a body at a distance of 20 cm from

the pivoted point.

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Answer 1

Answer:

1 Nm

Step-by-step explanation:

Force (F) = 5N

Distance (r) = 20cm = 0.2m

Moment of force (tau) ,

$= r \times f \\ = 0.2 \times 5 \\ = 1$

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