Question

calculate the moment of force of 5n applied on a body at a distance of 20cm from a pivoted point





please solve this numerical​

Answer 1

Answer:

Moment of force is calculated as:

Force x (perpendicular distance between point of application of force and axis of rotation)

But the unit should of the same system, SI or CGS

Here, Force = 10 N

     Distance = 30/100 = 0.3 m

Hence, Moment of force = 10x0.3 Nm

                                         = 3 Nm

Explanation:

you can change the digits and do it in the same way.

Answer 2

${ \rm{\large \underline \green{given}}}$

${ \rm{the \: moment \: of \: force = 5n}}$

${ \rm{the \: body \: at \: a \: distance = 20 \: cm}}$

${ \rm{ \large \underline \red{to \: find}}}$

$\: \: \: \: \: { \rm{the \: moment \: of \: force \: or \: torque}}$

$\textbf{ \large \underline{ \purple{solution}}}$

${ \rm{f = 10 \: r = 20cm = 0.2m}}$

${ \rm{ \large{moment \: of \: force = f \times r = 10 \times 0.2 = 2Nm}}}$

${ \rm{so \: the \: moment \: of \: force \: is \: 2Nm}}$