Question

Calculate the momentum of a photon of energy 6(10^-19)joule

Answer 1

we know,
energy of photon = hc/lemda
lemda = hc/energy of photon

lemda = 6.626 × 10^-34 × 3 × 10^8/6× 10^-19 m

now,
momentum of photon = h/lemda

= 6.626× 10^-34/{6.626×10^-34×3×10^8/6×10^-19 } kgm/s

= 6× 10^-19/3 × 10^8

= 2 × 10^-27 kg.m/s

Answer 2

Answer:2*10^-27

Explanation:

E=hc/lamda

(Since: h/lambda=p)

E=p*c

Or

P=E/c =>(6*10^-19)/(3*10^8)

=2*10^-27 j/ms