calculate the no. of aluminium ions in 0.05 g of aluminium oxide.
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Molecular weight of Al2O3 = 102 g.
102 g of Al2O3 contains 6.022X1023 molecules.
0.051g of Al2O3 contain X number of molecules.
X = 0.051 X 6.022X1023 /102 = 0.003 X 1020
X = 3 X 1020
1 molecule of Al2O3 contains – 2 Al+3ions.
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