calculate the no. of aluminium ions present in 0.051gram of
AL O
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raamjivr:
ooh
right answer is?
ya i visited 2 sites both of there ans is 6.022*10^20
tell me the answer alone
Then my answer is correct
why
I've given it in grams
ooo
27g of Al contains 6.022*10^23 atoms
0.027g contains 6.022*10^20 ions
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