Calculate the no of Aluminium ions present in 1.02g of Aluminium oxide.(Atomic mass of Al = 27u, O = 16u)
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1 mole of Al
2
O
3
=2×27+3×16
=102g
Moles of Al
2
O
3
=
102
0.051
=5×10
−4
moles
1 mole contains 6.02×10
23
molecules
∴5×10
−4
g of Al
2
O
3
contains = 5×10
−4
×6.02×10
23
=3.011×10
20
molecule
no. of Al
3+
ions in 1 molecules of Al
2
O
3
is 2.
∴ No. of aluminium ions will be:-
2×3.011×10
20
=6.022×10
20
.
Explanation:
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