Question

Calculate the no. of atoms in 0.23 g Na​

Answer 1

Answer:

6.022*10^21 atoms

Explanation:

1 mole of an element contains 6.022*10^23 atoms. (Avogadro number)

The gram atomic mass of Na is 23g.

The given weight is 0.23g

So number of moles of Na = Given weight/atomic weight = 0.23/23 = 0.01 moles

Since 1 mole contains 6.022*10^23 atoms, 0.01 moles will contain 6.022*10^23 * 0.01 = 6.022*10^21 atoms