Question

calculate the no. of atoms in 32gm of He​

Answer 1

Explanation:

6.022 ×8

hope it will help ful

Answer 2

Explanation:

properquesion

calculate number of atoms in 32g at helium

\boxed{$\colour{green}{Answer }$

\underline{formula}

formula

number \: of \: atoms = \frac{give \: mass}{molar \: mass} \times avogadro \: numbernumberofatoms=

molarmass

givemass

×avogadronumber

given mass of helium =32g

molar mass=atomic mass of helium

=2+2

=4u

avogadro number =\boxed{6.022 * 10^23}

6.022∗10

2

3

number \: of \: atoms = \frac{32g}{4u} \times 6.022 \times 10 { }^{23}numberofatoms=

4u

32g

×6.022×10

23

= 8 \times 6.022 \times 10 {}^{23}=8×6.022×10

23

= 48.176 \times 10 {}^{23} atoms=48.176×10

23

atoms