Chemistry, asked by Rizal1, 11 months ago

Calculate the no. of atoms of Ca present in 58.4g of CaCo3

Answers

Answered by KokilaAbhishek

0

Explanation:

one atom is present in CaCO3

Answered by shweta4341

0

Answer:

Explanation:

No of atoms = moles *nA* atomicity

= Moles = gievn mass/ molar mass that is = 58.4/100=0.584

Na= avagdros no

Atomicity= total no pf atoms = 5

So no of atoms = 0.584*6.022*10^23*5= 1.758*10^22 atoms

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