Calculate the no. of atoms of each element persent in 9.8 g of sulphuric acid, H2SO4. (H=1, S=32, O=16)
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• Total molecular weight of sulfuric acid =98
• Therefore number of moles in 9.8 gm of H2SO4=9.8/98=0.1 moles
• If one mole contains 6.023*1023 molecules, o mole would have 0.6023*1023 molecules
• Number of Hydrogen atoms in 0.1 mole= 2*6.023*1022
• Number of sulfur atoms=6.023*1022
• Number of oxygen atoms=24.092* 1022
• Therefore number of moles in 9.8 gm of H2SO4=9.8/98=0.1 moles
• If one mole contains 6.023*1023 molecules, o mole would have 0.6023*1023 molecules
• Number of Hydrogen atoms in 0.1 mole= 2*6.023*1022
• Number of sulfur atoms=6.023*1022
• Number of oxygen atoms=24.092* 1022
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