Question

calculate the no. of atoms of phosphorus in 284g of P4.
atomic mass of P→ 31 u​

Answer 1

Answer:

220.5728×10^23 atoms ,or,

2.205728×10^25 atmos

Explanation:

31u is atomic mass

so gram atomic mass is 31g

so gram atomic mass is equal to mass of 1mol of that element

so which is molar mass

so malar mass of p4 is 31g/mol

no of moles of p is

284/31=9.16 mole

so in p4 the atomicity of element is 4

so there 4 atoms in 1 p4 molecule

so in 9.16 mol of p4 molecule

there is 9.16×4mol of atoms= 36.64 mol of atoms

1 mol = 6.02×10^23

so 36.64mol =36.64×6.02×10^23

= 220.5728×10^23 atoms

or , 2.205728×10^25atoms