calculate the no. of atoms present in 11.5 litres of H2 at N.T.P.
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We know that, at STP /NTP, 1 mole of any gas contains 22.4 L of it.
So, 22.4 L of H2 = 1 mole.
so11.5 L of H2 = (1/22.4 ) x 11.5 mole = 0.51 moles of H2 gas.
As ,1 mole of H2 = 6.022 x 10^23molecules of H2
= 2 x 6.022 x 10^23atoms of H2
Hence, 0.51 mole of = 2 x 6.022 x 10^23
0.51 atoms of H2 = 6.14 x 10^23 atoms of H2
So, 22.4 L of H2 = 1 mole.
so11.5 L of H2 = (1/22.4 ) x 11.5 mole = 0.51 moles of H2 gas.
As ,1 mole of H2 = 6.022 x 10^23molecules of H2
= 2 x 6.022 x 10^23atoms of H2
Hence, 0.51 mole of = 2 x 6.022 x 10^23
0.51 atoms of H2 = 6.14 x 10^23 atoms of H2
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