Question

write a Pythagorean triplet whose smallest number 6

Answer 1

The Pythagoras triplet whose smallest number is 6 is as belows :
6, 8,10

Let's verify :
6^2 +8^2 = 10^2
36+64= 100
100 = 100
Hence verified


BE BRAINLY

Answer 2

Heya!!Here is your answer friend ⤵⤵
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⏪ The members of a Pythagorean Triplet are ,


$2m \: \: m {}^{2} - 1 \: and \: m {}^{2} + 1 \\ here \: 2m = 6 \\ m = 3 \\ 3 {}^{2} - 1 = 8 \\ 3 {}^{2} + 1 = 10$
Hence the triplet is 6, 8 and 10.


VERIFICATION :

$10 {}^{2} = 8 {}^{2} + 6 {}^{2} \\ 100 = 64 + 36 \\ 100 = 100$
Hence verified



Hope it helps you ✌✌