Question

Calculate the no. of atoms present in 180gm of glucose.

Answer 1

Hello

1 mole = avagadros number.

Formula of Glucose is C6H12O6

Calculating the Molar mass of Glucose:-

6(12)+1(12)+6(16) = 180gm.

1 mole = 180gm.

So, 180gm. of glucose contains avagadros number of atoms.

hence number of atoms in 180gm of glucose is 6.022 × 10²³

Answer 2

Answer: Given:-Mass of glucose = 180g

To find:-

→Number of moles in 180g of glucose

Solution:-

Chemical formula of glucose:-

=>C⁶H¹²O⁶

Thus,three elements are present in glucose i.e. Carbon, Hydrogen and Oxygen

•Atomic mass of Carbon = 12u

•Atomic mass of Hydrogen = 1u

•Atomic mass of Oxygen = 16u

Thus,molecular mass of glucose:-

=>12(6)+1(12)+16(6)

=>72+12+96

=>180u

Molecular mass of glucose is 180u

..Molar mass of glucose is 180g.

Now,number of moles:-

=>Given Mass/Molar mass

=>180/180

=>1 mole

Thus, 1 mole is present in 180g of glucose.