Question

calculate the no. of atoms present in 1g of nitrogen​

Answer 1

_____@Deepak Razput

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Answer 2

Answer: Here's your answer!!!!

Explanation: Mass of nitrogen=1gram

Molar mass of Nitrogen=14 g/mol

No. of moles of nitrogen=1/14

Now, we know that no. of moles =no. of atoms(N)/Avagadro's no.

1/14=(N)/6.022*10^23

N=6.022*10^23/14

N=0.430*10^23

N=4.3*10^22

Hence no. of atoms in 1 gram of nitrogen=4.3*10^23

Hope it helps!!!!