Calculate the no. of atoms present in 20g na2 co3
Answers
Answered by
2
no of moles Na2CO3 = 20/82
=10/41
no .of molecules =10/41 Na
no.of total atom = 6×10/41Na
=60/41 Na
=10/41
no .of molecules =10/41 Na
no.of total atom = 6×10/41Na
=60/41 Na
Similar questions